Answer:
Option C
Explanation:
Given,
Length of the pendulum(l)=1 cm
$\therefore$ amplitude (a) = path length/2=$\frac{16}{2}$=8 cm
Acceleration due to gravity (g) = $\pi^{2} m/s^{2}$
We know that, time period (T)= $2\pi\sqrt{\frac{l}{g}}=2\pi\sqrt{\frac{1}{\pi^{2}}}$
=$T=\frac{2\pi}{\pi}$
T=2s
$\therefore$ Maximum velocity (Vmax)= a $\omega$
= $a\times\frac{2 \pi}{T} $ $ \left( \because \omega=\frac{2\pi}{T}\right)$
$=\frac{8\times2\times \pi}{2}=8\pi cm/s$
